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Kd to pKd and ΔG, converted.

Type a dissociation constant, a pKd or a binding free energy; the other two follow at once, at the temperature you set. The formulas and worked examples are below.

Last updated September 16, 2026

Converter

The equilibrium dissociation constant. Lower is tighter binding.

−log₁₀ of Kd in molar units.

Standard binding free energy, RT ln Kd. Negative for spontaneous binding.

In kelvin. 298.15 K is 25 °C; 310.15 K is 37 °C.

Results

pKd
7.921
Kd
12 nM
ΔG°, kcal/mol
−10.81
ΔG°, kJ/mol
−45.21
Ka = 1/Kd
8.333e7 M⁻¹
RT at this temperature
2.479 kJ/mol0.5925 kcal/mol

Ki from IC50 · an approximation

Cheng and Prusoff, 1973

Cheng–Prusoff: IC50 to Ki

For a competitive inhibitor measured at equilibrium, Ki = IC50 / (1 + [S]/Km) in an enzyme assay, or Ki = IC50 / (1 + [L]/Kd) in a competition binding assay. The result holds only under those conditions; it is not a Kd, and it shifts with the concentration of substrate or tracer used.

Substrate or tracer concentration in the assay, same unit as IC50.

Of the substrate or tracer, same unit.

33.33 nM

Ki = IC50 / (1 + [S]/Km)

Cheng and Prusoff, 1973. Valid for competitive inhibition at equilibrium and when the inhibitor is not depleted; not valid for tight binding, irreversible or non-competitive inhibitors.

The formulas

Three numbers, one equilibrium

Kd
Kd = [A][B] / [AB] = koff / kon
The equilibrium dissociation constant, in molar units. It is the concentration of free ligand at which half the target sites are occupied.
pKd
pKd = −log₁₀(Kd / M)
A dimensionless logarithm: 1 nM is pKd 9, 1 µM is pKd 6. One pKd unit is a tenfold change in Kd and 1.364 kcal/mol at 25 °C.
ΔG°
ΔG° = RT ln Kd = −RT ln Ka = −2.303 RT · pKd
The standard binding free energy, taking Kd relative to the 1 M standard state. R = 8.314 462 618 J·mol⁻¹·K⁻¹ (CODATA 2018, exact); 1 kcal = 4.184 kJ (thermochemical calorie).
RT
RT(298.15 K) = 2.479 kJ/mol = 0.5925 kcal/mol
So at 25 °C, ΔG° in kcal/mol is about −1.364 × pKd; at 37 °C the factor is −1.419.

Worked examples

R = 8.314 462 618 J·mol⁻¹·K⁻¹

By hand, at 298.15 K

Each row is computed from the formulas above; the calculator reproduces every value.

Worked examples: Kd, pKd and ΔG° at 298.15 K unless stated.
KdpKdΔG°, kcal/molΔG°, kJ/molNote
12 nM7.921−10.81−45.21ln(1.2 × 10⁻⁸) = −18.238; × 2.4790 kJ/mol
3.2 nM8.495−11.59−48.49a low-nanomolar binder
250 pM9.602−13.10−54.81one log unit tighter than 2.5 nM: −1.364 kcal/mol more
1.5 µM5.824−7.945−33.24a typical fragment-screening hit
1 mM3.000−4.093−17.12the weak end of the scale
12 nM at 310.15 K7.921−11.24−47.03the same Kd at 37 °C; pKd does not change, ΔG° does

Questions

What the numbers mean

What is pKd?

The negative base-10 logarithm of the dissociation constant Kd expressed in molar units. A Kd of 1 nM is pKd 9; 10 nM is pKd 8. Working in pKd keeps affinities that span six orders of magnitude on one comparable, roughly linear scale.

Why is ΔG = RT ln Kd?

At equilibrium the standard free energy of a reaction is −RT ln K for its equilibrium constant K. For binding, the association constant Ka = 1/Kd, so ΔG° = −RT ln Ka = RT ln Kd, with Kd in molar units relative to the 1 M standard state. A negative ΔG° means binding is favorable.

Is Ki the same as Kd?

No. Ki is an inhibition constant from a competition experiment and Kd a dissociation constant from a direct binding experiment. For a competitive inhibitor at equilibrium they coincide, and Cheng–Prusoff converts an IC50 into Ki; IC50 itself depends on assay conditions and is not interchangeable with either.

Does temperature change pKd?

Not in this converter: pKd is defined from Kd alone. The temperature enters through RT, so ΔG° computed from the same Kd is larger in magnitude at 37 °C than at 25 °C. A measured Kd does itself change with temperature, by the van 't Hoff relation, but that is a property of the system, not of the conversion.

Sources

A reference tool. It performs a unit conversion and does not predict, measure or rank anything; nothing here is an Epitorix performance figure.

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